A point D is taken on the side BC of a...

Home / Arithmetic Ability / Triangles / Question

Examveda

A point D is taken on the side BC of a right-angled triangle ABC, where AB is hypotenuse. Then

A. AB² + CD² = AD² + BC²

B. CD² + BD² = 2AD²

C. AB² + AC² = 2AD²

D. AB² = AD² + BC²

Answer: Option A

Solution(By Examveda Team)

According to question,
Triangles mcq solution image

Triangles mcq solution image

In ΔABC
AB² = AC² + BC² . . . . . . . (i)
ΔACD
AD² = AC² + CD²
AC² = AD² - CD² . . . . . . . (ii)
Put the value of AC² in equation (i)
AB² = AD² - CD² + BC²
AB² + CD² = AD² + BC²

This Question Belongs to Arithmetic Ability >> Triangles

Join The Discussion

Related Questions on Triangles

If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:

A. 50°

B. 70°

C. 60°

D. 80°

View Answer

In the following figure which of the following statements is true?

A. AB = BD

B. AC = CD

C. BC + CD

D. AD < Cd

View Answer

In triangle PQR length of the side QR is less than twice the length of the side PQ by 2 cm. Length of the side PR exceeds the length of the side PQ by 10 cm. The perimeter is 40 cm. The length of the smallest side of the triangle PQR is :

A. 6 cm

B. 8 cm

C. 7 cm

D. 10 cm

View Answer

AB and CD bisect each other at O. If AD = 6 cm. Then BC is :

A. 5.9 cm

B. 4.8 cm

C. 6 cm

D. 7 cm

View Answer

More Related Questions on Triangles