A point D is taken on the side BC of a right-angled triangle ABC, where AB is hypotenuse. Then
A. AB2 + CD2 = AD2 + BC2
B. CD2 + BD2 = 2AD2
C. AB2 + AC2 = 2AD2
D. AB2 = AD2 + BC2
Answer: Option A
Solution (By Examveda Team)
According to question,
In ΔABC
AB2 = AC2 + BC2 . . . . . . . (i)
ΔACD
AD2 = AC2 + CD2
AC2 = AD2 - CD2 . . . . . . . (ii)
Put the value of AC2 in equation (i)
AB2 = AD2 - CD2 + BC2
AB2 + CD2 = AD2 + BC2
This Question Belongs to Arithmetic Ability >> Triangles
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