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In triangle PQR length of the side QR is less than twice the length of the side PQ by 2 cm. Length of the side PR exceeds the length of the side PQ by 10 cm. The perimeter is 40 cm. The length of the smallest side of the triangle PQR is :
Answer & Solution
Correct Answer:
Option
B
In δ PQR,
QR + 2 = 2PQ
QR = 2PQ - 2 - - - - - - - (1)
PR = PQ + 10 - - - - - - (2)
Perimeter = 40 m PQ + QR + Rp = 40 Putting the value of PQ and QR from equation (1) and (2), PQ + 2PQ - 2 + PQ + 10 = 40 4PQ = 32 PQ = 8 cm which is the smallest side of the triangle.
Perimeter = 40 m PQ + QR + Rp = 40 Putting the value of PQ and QR from equation (1) and (2), PQ + 2PQ - 2 + PQ + 10 = 40 4PQ = 32 PQ = 8 cm which is the smallest side of the triangle.
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LoginLength of PQ = x cm,
Length of PR = y cm,
Length of QR = z cm
Length of the side QR is less than twice the length of the side PQ by 2 cm
i.e., z = 2x - 2
Length of the side PR exceeds the length of the side PQ by 10 cm
i.e., y = x + 10
x + y + z = 40
x + (x+10) + (2x-2) = 40
4x + 8 = 40
4x = 40 - 8 = 32
x = 32/4 = 8 cm
x = 8 cm
y = x + 10 = 10 + 8 = 18 cm
z = 2x - 2 = (2 * 8) - 2 = 16 - 2 = 14 cm
Smallest side of the triangle = x = 8 cms