ExamVeda
Login
Home
Machine Design
?

A shaft is subjected to fluctuating loads for which the normal torque (T) and bending moment (M) are 1000 N-m and 500 N-m respectively. If the combined shock and fatigue factor for bending is 1.5 and combined shock and fatigue factor for torsion is 2, then the equivalent twisting moment for the shaft is

Answer & Solution
Correct Answer: Option D
Let's discuss the solution. Join the discussion
Examveda
Question posted by Examveda
Community

Join the Discussion

8 Comments
Yerosan Yadesa
Yerosan Yadesa 3 years ago
T₁= √(1.5x500) + (2x1000)² =2136 N-m
BISWAJIT
BISWAJIT 5 years ago
We know that equivalent twisting moment
T₁= √√(KXM)² + (K,XT)² Since T = 1000 N-m; M = 500 N-m; K=1.5 and K,= 2, therefore
T₁= √(1.5x500) + (2x1000)² =2136 N-m
THANK YOU
Kartavya Sagar
Kartavya Sagar 5 years ago
Teq = { (km * M)^2 + (kt * T)^2}^1/2
Sarveshwer Chandra
Sarveshwer Chandra 6 years ago
Sqrt [(2*1000)^2 + (1.5*500)^2].
Anju Prasad
Anju Prasad 6 years ago
Need full solutions
Ganesh Niture
Ganesh Niture 6 years ago
How?
Muhammad Usman
Muhammad Usman 6 years ago
Te=[(M*Kf)^2+(T*Kb)^2]^1/2
AGALDEETI SUNIL
AGALDEETI SUNIL 6 years ago
Explain me