ABC is a right-angled triangle with AB = 6 cm and BC = 8 cm. A circle with center O has been inscribed inside ΔABC. The radius of the circle is

A. 1 cm

B. 2 cm

C. 3 cm

D. 4 cm

Answer: Option B

Solution(By Examveda Team)

According to question,
Given :

AB = 6 cm,         BC = 8 cm
In right angle ΔABC
By using Pythagoras theorem
AC² = AB² + BC²
AC² = 6² + 8²
AC² = 36 + 64
AC² = 100
AC  = 10 cm
In radius
$$\eqalign{ & = \frac{{a + b - c}}{2} \cr & = \frac{{8 + 6 - 10}}{2} \cr & = \frac{4}{2} \cr & = 2\,cm \cr} $$