ABC is a triangle in which ∠A = 90°. Let P be any point on side AC. If BC = 10 cm, AC = 8 cm and BP = 9 cm, then AP = ?
A. $$2\sqrt 5 $$ cm
B. $$3\sqrt 5 $$ cm
C. $$2\sqrt 3 $$ cm
D. $$3\sqrt 3 $$ cm
Answer: Option B
Solution(By Examveda Team)
According to question,BC = 10 cm, AC = 8 cm, BP = 9 cm
In ΔCAB,
BC2 = AB2 + AC2
102 = AB2 + 82
AB2 = 100 - 64
AB2 = 36
AB = 6 cm
In ΔPAB
BP2 = AB2 + AP2
92 = 62 + AP2
AP2 = 81 - 36
AP2 = 45
AP = $$3\sqrt 5 $$ cm
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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