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ABC is a triangle in which ∠A = 90°. Let P be any point on side AC. If BC = 10 cm, AC = 8 cm and BP = 9 cm, then AP = ?
Answer & Solution
Correct Answer:
Option
B
According to question,
BC = 10 cm, AC = 8 cm, BP = 9 cm
In ΔCAB,
BC2 = AB2 + AC2
102 = AB2 + 82
AB2 = 100 - 64
AB2 = 36
AB = 6 cm
In ΔPAB
BP2 = AB2 + AP2
92 = 62 + AP2
AP2 = 81 - 36
AP2 = 45
AP = $$3\sqrt 5 $$ cm
BC = 10 cm, AC = 8 cm, BP = 9 cm
In ΔCAB,
BC2 = AB2 + AC2
102 = AB2 + 82
AB2 = 100 - 64
AB2 = 36
AB = 6 cm
In ΔPAB
BP2 = AB2 + AP2
92 = 62 + AP2
AP2 = 81 - 36
AP2 = 45
AP = $$3\sqrt 5 $$ cm
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