ABC is a triangle. The bisectors of the internal angle ∠B and external angle ∠C intersect at D. If ∠BDC = 50°, then ∠A is
A. 100°
B. 90°
C. 120°
D. 60°
Answer: Option A
Solution (By Examveda Team)
According to question,
Given :
∠D = 50°
∠BAC = 2∠BDC (property)
∴ ∠BAC = 2 × 50°
∠BAC = 100°
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