ABC is an isosceles triangle such that AB = AC and ∠B = 35°, AD is the median to the base BC. Then ∠BAD is
A. 70°
B. 35°
C. 110°
D. 55°
Answer: Option D
Solution(By Examveda Team)
According to question,AB = AC, ∠B = ∠C
∠A + ∠B + ∠C = 180°
∠A + 2∠B = 180°
∠A = 180° - 70°
∠A = 110°
Note : In isosceles triangle median bisects the opposite side and make angle 90° on opposite side. It also bisects the vertex angle.
∠BAD = $$\frac{{\angle A}}{2}$$
∠BAD = $$\frac{{{{110}^ \circ }}}{2}$$
∠BAD = 55°
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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