ABC is an isosceles triangle such that AB = AC and ∠B = 35°, AD is the median to the base BC. Then ∠BAD is

According to question,

AB = AC,         ∠B = ∠C
∠A + ∠B + ∠C = 180°
∠A + 2∠B = 180°
∠A = 180° - 70°
∠A = 110°
Note : In isosceles triangle median bisects the opposite side and make angle 90° on opposite side. It also bisects the vertex angle.
∠BAD = $$\frac{{\angle A}}{2}$$
∠BAD = $$\frac{{{{110}^ \circ }}}{2}$$
∠BAD = 55°