An amount of Rs. 680 was invested at 6% rate of interest and another sum of money was invested at 10% interest. If the average interest on the total at the end of the year was 7.5%, how much was invested at 10%?
A. Rs. 408
B. Rs. 412.6
C. Rs. 267.5
D. None of these
Answer: Option A
Solution(By Examveda Team)
Now, $$\frac{{680}}{x} = \frac{{2.5}}{{1.5}}$$ Or, $$x = \frac{{680 \times 3}}{5}$$ Hence, x = Rs. 408
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Related Questions on Alligation
A. $$\frac{{1}}{{2}}$$ kg
B. $$\frac{{1}}{{8}}$$ kg
C. $$\frac{{3}}{{14}}$$ kg
D. $$\frac{{7}}{{9}}$$ kg
A. 81 litres
B. 71 litres
C. 56 litres
D. 50 litres
answer must be 255
408 answer is correct ,because 680 amount given only at 6 % interest rate . Not both rates
Answer must be 255 at 10% and 425 at 6%
Nice method.
the ans should be 255...
In allegation formula we put
Cheap price. Costly price
Avgprice
Cheap commodity : costly commodity ratio
That is 2.5:1.5
Or 5:3
So acc to the formula ratio for 10% is 3
Then we will ger 3*680/8= 255/-
How did u do that...pls explain
What is this method called? The cross ratio one. I want to learn it.
Can any 1 solve this ques by using simple interest formula
It can be solve by using simpleinterest formula but we can save time by using this method so it is best
Ratio is clearly showing is 5:3, hence investment is 10% is 3/8*680=255
ans is given 480 and in soln part it is 408 . which is currect