ExamVeda
Login
Home

Speed Time And Distance - Aptitude MCQ Questions and Solutions with Explanations

Speed Time And Distance MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Speed Time And Distance with easy and logical explanations. Speed Time And Distance MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-7 section-5

Each section contains 100 MCQs on Speed Time and Distance .
61
A man walks from point X to Y at a speed of 20 km/h, but comes back from point Y to X at a speed of 25 km/h. Find his average speed.
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\eqalign{ & {\text{Average speed}} = \frac{{2 \times 20 \times 25}}{{20 + 25}} \cr & = \frac{{2 \times 20 \times 25}}{{45}} \cr & = \frac{{200}}{9} \cr & = 22\frac{2}{9}{\text{ km/h}} \cr} $$
62
Richa travels from A to B at the speed of 15 km/h, from B to C at 20 km/h, and from C to D at 30 km/h. If AB = BC = CD, then find the Richa's average speed.
Discuss
Answer & Solution
Answer: Option D
Solution:
Let AB = BC = CD = 60 km (LCM of 15, 20 and 30)
Total distance = 3 × 60 = 180 km
Time taken by Richa to travels from A to B = $$\frac{{60}}{{15}}$$ = 4 hrs.
Time taken by Richa to travels from B to C = $$\frac{{60}}{{20}}$$ = 3 hrs.
Time taken by Richa to travels from C to D = $$\frac{{60}}{{30}}$$ = 2 hrs.
Total time taken by Richa to travels from A to D = 4 + 3 + 2 = 9 hrs.
∴ Average speed = $$\frac{{180}}{9}$$ = 20 km/hr.
63
A car covers 15 km, 20 km, 30 km and 12 km at speeds of 20 km/h, 30 km/h, 40 km/h and 30 km/h, respectively. The average speed of the car for the total journey is:
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Average speed}} = \frac{{{\text{Total distance}}}}{{{\text{Total time}}}} \cr & = \frac{{15 + 20 + 30 + 12}}{{\frac{3}{4} + \frac{2}{3} + \frac{3}{4} + \frac{2}{5}}} \cr & = \frac{{27}}{{\frac{3}{2} + \frac{2}{3} + \frac{2}{5}}} \cr & = \frac{{77 \times 30}}{{45 + 20 + 12}} \cr & = \frac{{77 \times 30}}{{77}} \cr & = 30 \cr & {\text{Average speed}} = 30{\text{ km/h}} \cr} $$