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True Discount - Aptitude MCQ Questions and Solutions with Explanations

True Discount MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on True Discount with easy and logical explanations. True Discount MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-10 section-1

Each section contains 100 MCQs on True Discount .
91
A shopkeeper marks his goods 20% above his cost price and gives 15% discount on the marked price. His gain percent is = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the cost price = Rs. 100
$$\eqalign{ & {\text{Market price }} \cr & {\text{ = 120}}\% {\text{ of 100 }} \cr & {\text{ = Rs}}{\text{. 120}} \cr & {\text{Selling price }} \cr & {\text{ = 85}}\% {\text{ of 120 }} \cr & {\text{ = }}\frac{{85}}{{100}} \times {\text{120 }} \cr & {\text{ = Rs}}{\text{. 102}} \cr & {\text{Gain }}\% = \frac{{102 - 100}}{{100}} \times 100 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 2\% \cr} $$
92
A shopkeeper sold an item for Rs. 1510 after giving a discount of $$24\frac{1}{2}\% $$   and there by incurred a loss of 10%. Had he sold the item without discount his net profit would have been = ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the marked price of an item = Rs. x
Selling price of an item $$ = \left( {100 - 24\frac{1}{2}} \right)\% \,{\text{of }}x$$
$$\eqalign{ & \Rightarrow 1510 = \frac{{151}}{2} \times \frac{1}{{100}} \times x \cr & \Rightarrow x = {\text{Rs}}{\text{. 2000}} \cr & {\text{Cost price of an item }} \cr & = 1510 \times \frac{{100}}{{90}} \cr & {\text{ = Rs}}{\text{. }}\frac{{15100}}{9} \cr & {\text{Without discount, gain}} \cr & {\text{ = }}2000 - \frac{{15100}}{9} \cr & = \frac{{18000 - 15100}}{9} \cr & = \frac{{2900}}{9} \cr & = {\text{Rs}}{\text{. 322}}\frac{2}{9} \cr} $$
93
Discount on a pair of shoes marked at Rs. 475 and discounted at 15% is = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Market price of shoes = Rs. 475
$$\eqalign{ & {\text{Discount}} = \frac{{15}}{{100}} \times 475 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{285}}{4}{\text{ }} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = Rs 71}}{\text{.25}} \cr} $$
94
A machine is marked at Rs. 6800 and available at a discount of 10%. The shopkeeper gives another off season discount to the buyer and sells the machine for Rs. 5202. Find the off season discount ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Marked price of machine = Rs. 6800
After 1st discount
$$\eqalign{ & = \frac{{90}}{{100}} \times 6800 \cr & = {\text{Rs}}{\text{. 6120}} \cr} $$
Selling price of machine = Rs. 5202
$$\eqalign{ & {\text{Discount }}\% \cr & = \frac{{6120 - 5202}}{{6120}} \times 100 \cr & = \frac{{918}}{{6120}} \times 100 \cr & = 15\% \cr} $$
95
A double bed is market at Rs. 75000. The shopkeeper allows successive discounts of 8%, 5% and 2% on it. What is the net selling price ?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & {\text{Net selling price }} \cr & {\text{ = }}\frac{{92}}{{100}} \times \frac{{95}}{{100}} \times \frac{{98}}{{100}} \times 75000 \cr & = {\text{Rs}}{\text{. 64239}} \cr} $$
96
Anand marks up the price of an article by 50% and then allows a discount of 20% and sells it to Balaji who sells it for Rs. 20, more than what he purchased for, this selling price is 30% more then the original cost price of the article. Then Balaji's profit % is = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let original cost price = 100 units
$$\eqalign{ & {\text{Cost price of Balaji }} \cr & {\text{ = 100}} \times \frac{{150}}{{100}} \times \frac{{80}}{{100}} \cr & {\text{ = 120 units}} \cr & {\text{Selling price of Balaji }} \cr & {\text{ = }}\frac{{130}}{{100}} \times 100\, \cr & {\text{ = 130 units}} \cr & {\text{Profit of Balaji }} \cr & {\text{ = 130}} - 120 \cr & = {\text{10 units}} \cr & {\text{Profit percent }} \cr & {\text{ = }}\frac{{10}}{{120}} \times 100 \cr & {\text{ = 8}}{\text{.33}}\% \cr} $$
Note: There is no use of Rs. 20 given in the question
97
The marked price of an article is Rs. 500. A shopkeeper gives a discount of 5% and still makes a profit of 25%. The cost price of the article is = ?
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & {\text{Cost price of the article}} \cr & {\text{ = 500}} \times \frac{{95}}{{100}} \times \frac{{100}}{{125}} \cr & = {\text{Rs}}{\text{. 380}} \cr} $$
98
A shopkeeper allows a discount of 12.5% on the marked price of a certain article and makes a profit of 20%. If the article costs the shopkeeper Rs. 210, then the marked price of the article will be = ?
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Market price of the article }} \cr & {\text{ = }}210 \times \frac{{120}}{{100}} \times \frac{{100}}{{87.5}} \cr & = {\text{Rs}}{\text{. 288}} \cr} $$
99
The difference between simple interest and the true discount on Rs. 2400 due 4 years hence at 5% per annum simple interest is -
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Given}}\,{\text{A}} = 2400 \cr & {\text{R}} = 5\% \cr & {\text{T}} = 4{\text{year}} \cr & \therefore \,TD\, = \frac{{A \times R \times T}}{{100 + R \times T}} \cr & TD = \frac{{2400 \times 4 \times 5}}{{100 + 20}} \cr & TD = {\text{Rs}}{\text{. }}400 \cr & \therefore \,{\text{S}}{\text{.I}}{\text{.}} - {\text{TD}} = \frac{{TD \times R \times T}}{{100}} \cr & = \frac{{400 \times 5 \times 4}}{{100}} \cr & = {\text{Rs}}{\text{. 80}}{\text{}} \cr} $$
100
Charging 30% above its production cost a radio maker puts a label of Rs. 286 on a radio as is price. But at the time of selling it, he allows 10% discount on the labelled price. What will his gain be ?
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Cost of ratio}} \cr & = \frac{{286}}{{130}} \times 100 \cr & = {\text{Rs}}{\text{. 220}} \cr & {\text{Selling price of ratio}} \cr & = 286 \times \frac{{90}}{{100}} \cr & = {\text{Rs 257}}{\text{.40}} \cr & {\text{Profit}} = 257.40 - 220 \cr & = {\text{Rs 37}}{\text{.40}} \cr} $$