Coding And Decoding - General Inteligence & Reasoning MCQ Questions and Answers
Learn Coding And Decoding mcq questions and answers with easy and logical explanations - Coding And Decoding is part of competitive reasoning mcq questions. Page-3 section-1
Given, A = 4, K = 3, N = 2, P = 1. Sum of first Set, = K + A + N + P +K = 3 + 4 + 2 + 1 + 3 = 13. Sum of the second set, N + P + A + K +N = 2 + 1 + 4 + 3 + 2 = 12. Sum of the third set, P + K + A + N + A = 1 + 3 + 4 + 2 + 3 = 13. Sum of the fourth set, N + A + K + N + A = 2 + 4 + 3 + 2 + 4 = 15.
Compare letters by position (original → code):
O R C H E S T R A → A R T S E O R C H
So the code takes the part after the first four letters (that is, from the 5th letter to the end), reverses that part, and then appends the first four letters unchanged.
In other words: code = reverse(original[5..end]) + original[1..4].
Apply this rule to DREAMLAND:
First four letters = DREA
Remaining part = MLAND
Reverse the remaining part: DNALM
Append the first four letters: DNALM + DREA = DNALMDREA
Thus the coded form of DREAMLAND is DNALMDREA (Option C).
Since every alternative letter starting from B of the English alphabet is written in small letter, the letters written in small letter are b, d, f, h and so on. And Capital letters are C, E, G so on. In option first, third and fourth e is written in small letter, so it cannot be the answer And In second option second e is written in small. Therefore, none of above options are satisfy the condition. .