Missing Number Finding - General Inteligence & Reasoning MCQ Questions and Answers

Reading each pair of numbers as 2 digit values, the sum of the 4 numbers is given in the top space in the diagram. I.e
156 = 26 + 31 + 45 + x
x = 54.
So, missing number = 4.

Number at lower segment = 2 * difference of number in left segment and right segment.
10 - 4 = 6
Let missing number is x.
x = 2 *6 = 12.

Row-wise:
First Element + Second Element - 2 = Third Element.
6 + 1 - 2 = 5
3 + 9 - 2 = 10
4 + 3 - 2 = x
x = 5.
Required Number = 5.

Reading each row as a 3 or 2 digit number, subtract the central 2 digit value from the upper 3 digit value, to give the 3 digit result on the lower row. I.e.
239 - 97 = 142.
So, required Missing number is 2.

Starting with the left hand circle, add 4 to each number and rotate their positions 1 place clockwise to give the values in the upper right hand circle.

And then add 5 to each of these values and rotate their positions 1 place clockwise to give the values in the lower right hand circle. So,

Missing Number = 5 + 5 = 10.

Column Wise,
First Element + Second Element = Third Element
48 + 24 = 72
30 + 15 = 45
So,
20 + 10 = 30.
Required Number = 30

From left to Right,
Numbers follow the sequence of multiples of 14, from 112 to 182, with each value being written back to front. I.e
112 = 211
126 = 621
140 = 041
154 = 451
168 = 861
and,
182 = 281
So, required number = 281.

Working from top to bottom,
The sum of the numbers in each row is put in the left hand box on the row below, and the difference between the two numbers in each row is put in the right hand box on the row below. I.e.

Row one First Element + Row one second element = Row two first Element.
Difference of first row elements = Row two second Element.
And So on.

Thus,
Row fifth first element + row fifth second element = Row sixth first element
32 + 12 = 44
And,
32 - 12 = 20 ( Row sixth second element).

Logic:
In each row, Center Element = Sum of other elements - 2
So required element,
= 5 +4 +3 + 9 + 2 + 1 -2
= 24 - 2
= 22.

In each diagram, the sum of the top two and middle digits equals the sum of the lower 2 digits. I.e
Sum of Upper elements + middle element = Sum of the lower elements

In first Diagram,
5 + 3 + 12 = 14 + 6 = 20
Second Diagram,
4 + 4 +2 = 5 + 5 = 10
Third Diagram,
6 + 1 + 8 = 12 + x
x = 3.
Required Element = 3.