Determine output:
public class Test{
public static void main(String[] args){
int[] x = {1, 2, 3, 4};
int[] y = x;
x = new int[2];
for(int i = 0; i < x.length; i++)
System.out.print(y[i] + " ");
}
}
public class Test{
public static void main(String[] args){
int[] x = {1, 2, 3, 4};
int[] y = x;
x = new int[2];
for(int i = 0; i < x.length; i++)
System.out.print(y[i] + " ");
}
}A. 1 2 3 4
B. 0 0 0 0
C. 1 2
D. 0 0
E. None of these
Answer: Option C
This Question Belongs to Java Program >> Array
previously y is initialized with x in that case y[4] and then later x is initialized with size 2 that means in for loop x.length means it size is 2 but initial value for "i" in for loop is given as zero that means it satisfies two conditions that is 0
a good explanation : http://stackoverflow.com/questions/34462460/how-does-x-new-int2-work-in-this-java-code