Digital Electronics MCQ Questions & Answers

Digital Electronics MCQ Questions & Answers | ECE

Learn Digital Electronics MCQ questions & answers are available for a Electronics and Communications Engineering(ECE) students to clear GATE exams, various technical interview, competitive examination, and another entrance exam. Digital Electronics MCQ question is the important chapter for a Electronics and Communications Engineering(ECE) and GATE students. Page-9 section-1

Consider the multiplexer based logic circuit shown in the figure
Digital Electronics mcq question image

Which one of the following Boolean functions is realized by the circuit?

A) $${\text{F}} = {\text{W}}{\overline {\text{S}} _1}{\overline {\text{S}} _2}$$ B) $${\text{F}} = {\text{W}}{{\text{S}}_1} + {\text{W}}{{\text{S}}_2} + {{\text{S}}_1}{{\text{S}}_2}$$ C) $${\text{F}} = \overline {\text{W}} + {{\text{S}}_1} + {{\text{S}}_2}$$ D) $${\text{F}} = {\text{W}} \oplus {{\text{S}}_1} \oplus {{\text{S}}_2}$$

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Answer & Solution

Answer: Option D

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Simplify the Boolean function F(w, x, y, z) = Σ(1, 3, 7, 11, 15) And the don't care conditions: d(w, x, y, z) = Σ(0, 2, 5)

A) F = zw + zy' B) F' = zw' + yz C) F' = z' + wy' D) F = z'w + zy'

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Answer & Solution

Answer: Option B

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A Boolean function f of two variables x and y is defined as follows:
f(0, 0) = f(0, 1) = f(1, 1) = 1; f(1, 0) = 0
Assuming complements of x and y are not available, a minimum cost solution for realizing f using only 2-input NOR gates and 2-input OR gates (each having unit cost) would have a total cost of

A) 1 unit B) 4 unit C) 3 unit D) 2 unit

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Answer & Solution

Answer: Option D

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Two's complement of the binary number 10010100 is

A) 01101011 B) 01101100 C) 11101100 D) 10001011

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Answer & Solution

Answer: Option B

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What is dual of A + [B + (AC)] + D

A) A + [B (A + C)] + D B) A[B + AC]D C) A + [B(A + C)]D D) A[B(A + C)]D

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Answer & Solution

Answer: Option D

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A 4 : 1 multiplexer requires . . . . . . . . data selection line.

A) 4 B) 2 C) 1 D) 16

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Answer & Solution

Answer: Option B

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In the 8421 BCD code the decimal number 125 is written as

A) 1111101 B) 7 D C) 000100100101 D) None of these

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Answer & Solution

Answer: Option C

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In figure below, U1 is a 4-bit binary synchronous counter with synchronous clear. Q₀ is the LSB and Q₃ is the MSB of the output.
The circuit shown in figure represents a:
Digital Electronics mcq question image

A) mod 2 counter B) mod 3 counter C) mod 4 counter D) mod 5 counter

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Answer & Solution

Answer: Option D

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D flip-flop can be made from J-K flip-flop by making:

A) J = K = 0 B) J = K = 1 C) J = 0, K = 1 D) $${\text{J}} = \overline {\text{K}} $$

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Answer & Solution

Answer: Option D

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The decimal equivalent of binary 1101.11 is

A) 9.75 B) 13.75 C) 11.50 D) 11.75

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Answer & Solution

Answer: Option B

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