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Find the odd number letters from the given alternatives

This question belongs to Competitive Reasoning Odd Man Out
Odd Man Out
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Find the odd number/letters from the given alternatives.

Answer & Solution
Correct Answer: Option D

ABYZ → (B+Y = 2+25 = 27) and (A+Z = 1+26 = 27.)
CDWX → (D+W = 4+23 = 27) and (C+X = 3+24 = 27.)
EFUV → (F+U = 6+21 = 27) and (E+V = 5+22 = 27.)
GHTV → (H+T = 8+20 = 28) and (7+22 = 29.)

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