For a triangle ABC, D, E, F are the mid - point of its sides. If ΔABC = 24 sq. units then ΔDEF is :

According to question,

As we know that
Given: area of ΔABC = 24 square units
As we know that
D, E and F are the midpoint of AB, AC and BC
∴ Area of ΔADE = area of ΔDBF
= area of ΔDEF = area of ΔEFC
∴ Area of ΔDEF = $$\frac{1}{4}$$ area of ΔABC
Area of ΔDEF = $$\frac{1}{4}$$ × 24
Area of ΔDEF = 6 sq. units