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From the marriage between two heterozygotes for albinism, what is the chance that the first would be non-albino
Answer & Solution
Correct Answer:
Option
D
From the marriage between two heterozygotes for albinism, the chance that the first would be non-albino is 3/4.
Albinism is the congenital absence of melanin in an animal or plant resulting in white hair, feathers, scales and skin, and pink or blue eyes. Individuals with the condition are referred to as albinos.
For two heterozygote parents (Aa), 1/4 of all offspring would be expected to show the recessive trait of albinism.
The chance of a child of these parents having normal skin color (Non-albino) is 3/4.
Albinism is the congenital absence of melanin in an animal or plant resulting in white hair, feathers, scales and skin, and pink or blue eyes. Individuals with the condition are referred to as albinos.
For two heterozygote parents (Aa), 1/4 of all offspring would be expected to show the recessive trait of albinism.
The chance of a child of these parents having normal skin color (Non-albino) is 3/4.
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Loginhow is it that 3/4 is the answer when 2 /4 have the same genotype as of parents (Aa) and 1/4 (AA)?