If in a triangle ABC, BE and CF are two medians perpendicular to each other and if AB = 19 cm and AC = 22 cm then the length of BC is :

A. 20.5 cm

B. 19.5 cm

C. 26 cm

D. 13 cm

Answer: Option D

Solution(By Examveda Team)

Given :
AB = 19 cm, AC = 22 cm
∵ BE ⊥ CF (given), [Medians CF & BE are perpendicular to each other]
⇒ In this case
⇒ We know,
   AB² + AC² = 5(BC)²
⇒ 19² + 22² = 5(BC)²
⇒ 361 + 484 = 5(BC)²
⇒ 845 = 5(BC)²
⇒ (BC)² = 169
⇒ BC = 13 cm