If in a triangle ABC, D and E are on the sides AB and AC, such that, DE is parallel to BC and $$\frac{{AD}}{{BD}}$$ = $$\frac{3}{5}$$. If AC = 4 cm, then AE is
A. 1.5 cm
B. 2.0 cm
C. 1.8 cm
D. 2.4 cm
Answer: Option A
Solution(By Examveda Team)
According to question,Given :
AD = 3
BD = 5
AB = 8
AC = 4
AE = ?
By applying B. P. T
$$\eqalign{ & \frac{{AD}}{{AB}} = \frac{{AE}}{{AC}} = \frac{{DE}}{{BC}} \cr & \frac{3}{8} = \frac{{AE}}{4} \cr & AE = \frac{3}{2} = 1.5\,{\text{cm}} \cr} $$
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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