If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to (Where, Pc is centrifugal tension)
A. $${\left( {\frac{{\sqrt {{{\text{P}}_1}} + \sqrt {{{\text{P}}_2}} }}{2}} \right)^2}$$
B. $${{\text{P}}_1} + {{\text{P}}_2}$$
C. $$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right)$$
D. $$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right) + {{\text{P}}_{\text{c}}}$$
Answer: Option A

D. [⅟₂ × (P1 + P2)] + Pc
(T1+T2/2) + Tc = T1 + T2 + 2Tc/2.
Option is D