If 'X' is a random variable, taking values 'X', probability of success and failure being 'p' and 'g' respectively and 'n' trials being conducted, then what is the probability that 'X' takes values 'x'? Use Binomial Distribution.

A. $$P\left( {X = x} \right) = {}^n{C_x}{p^x}{q^x}$$

B. $$P\left( {X = x} \right) = {}^n{C_x}{p^x}{q^{\left( {n - x} \right)}}$$

C. $$P\left( {X = x} \right) = {}^x{C_n}{q^x}{p^{\left( {n - x} \right)}}$$

D. $$P\left( {x = x} \right) = {}^x{C_n}{p^n}{q^x}$$

Answer: Option B