In a reversible adiabatic process, the ratio of T_1T_2 is equal to

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Engineering Thermodynamics

In a reversible adiabatic process, the ratio of $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}}$$ is equal to

A) $${\left( {\frac{{{{\text{p}}_2}}}{{{{\text{p}}_1}}}} \right)^{\gamma - \frac{1}{\gamma }}}$$ B) $${\left( {\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}} \right)^{\gamma - \frac{1}{\gamma }}}$$ C) $${\left( {\frac{{{{\text{v}}_2}}}{{{{\text{v}}_1}}}} \right)^{\gamma - \frac{1}{\gamma }}}$$ D) $${\left( {\frac{{{{\text{v}}_1}}}{{{{\text{v}}_2}}}} \right)^{\gamma - \frac{1}{\gamma }}}$$

Answer & Solution

Correct Answer: Option B

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In a reversible adiabatic process the ratio of frac text T...

In a reversible adiabatic process, the ratio of $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}}$$ is equal to

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