In a right-angle ΔABC, ∠ABC = 90°, AB = 5 cm and BC = 12 cm. The radius of the circumcircle of the triangle ABC is
A. 7.5 cm
B. 6 cm
C. 6.5 cm
D. 7 cm
Answer: Option C
Solution(By Examveda Team)
According to question,ABC is a right angled triangle
∴ By using Pythagoras theorem
AC2 = AB2 + BC2
AC2 = (5)2 + (12)2
AC2 = 25 + 144
AC2 = 169
AC = $$\sqrt {169} $$
AC = 13 cm
BD = IR = Circumradius = $$\frac{{AC}}{2}$$
∴ IR = $$\frac{{13}}{2}$$
IR = 6.5 cm
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
Join The Discussion