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In a right-angle ΔABC, ∠ABC = 90°, AB = 5 cm and BC = 12 cm. The radius of the circumcircle of the triangle ABC is
Answer & Solution
Correct Answer:
Option
C
According to question,
ABC is a right angled triangle
∴ By using Pythagoras theorem
AC2 = AB2 + BC2
AC2 = (5)2 + (12)2
AC2 = 25 + 144
AC2 = 169
AC = $$\sqrt {169} $$
AC = 13 cm
BD = IR = Circumradius = $$\frac{{AC}}{2}$$
∴ IR = $$\frac{{13}}{2}$$
IR = 6.5 cm
ABC is a right angled triangle
∴ By using Pythagoras theorem
AC2 = AB2 + BC2
AC2 = (5)2 + (12)2
AC2 = 25 + 144
AC2 = 169
AC = $$\sqrt {169} $$
AC = 13 cm
BD = IR = Circumradius = $$\frac{{AC}}{2}$$
∴ IR = $$\frac{{13}}{2}$$
IR = 6.5 cm
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