In a triangle ABC,∠ A = 90°, AL is drawn perpendicular to BC, Then ∠BAL is equal to:

A. ∠ALC

B. ∠ACB

C. ∠BAC

D. ∠B - ∠BAL

Answer: Option B

Solution(By Examveda Team)

∠BAL + ∠B + 90° = 180°
or, ∠BAL + ∠B = 90°
or, ∠BAL = 90° - ∠B - - - - - - - - (1)
Now, in ΔABC,
∠ACB + ∠B + ∠A = 180°
∠ACB = 90°
-∠B - - - - - (2)
From, (1) and (2),
∠BAL = ∠ACB