In a triangle ABC,∠ A = 90°, AL is drawn perpendicular to BC, Then ∠BAL is equal to:
A. ∠ALC
B. ∠ACB
C. ∠BAC
D. ∠B - ∠BAL
Answer: Option B
Solution(By Examveda Team)
∠BAL + ∠B + 90° = 180°or, ∠BAL + ∠B = 90°
or, ∠BAL = 90° - ∠B - - - - - - - - (1)
Now, in ΔABC,
∠ACB + ∠B + ∠A = 180°
∠ACB = 90°
-∠B - - - - - (2)
From, (1) and (2),
∠BAL = ∠ACB
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Comments ( 1 )
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