In a ΔABC, BC is extended upto D; ∠ACD = 120°, ∠B = $$\frac{1}{2}$$ ∠A, then ∠A is:
A. 60°
B. 75°
C. 80°
D. 90°
Answer: Option C
Solution (By Examveda Team)
∠C = 180° - 120° = 60°
∠A + ∠B + ∠C = 180°
∠A + $$\frac{1}{2}$$ ∠A + 60° = 180°
$$\frac{3}{2}$$ ∠A = 120°
∠A = 80°
This Question Belongs to Arithmetic Ability >> Triangles
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