In a ΔABC, BC is extended upto D; ∠ACD = 120°, ∠B = $$\frac{1}{2}$$ ∠A, then ∠A is:

A. 60°

B. 75°

C. 80°

D. 90°

Answer: Option C

Solution(By Examveda Team)

∠C = 180° - 120° = 60°
∠A + ∠B + ∠C = 180°
∠A + $$\frac{1}{2}$$ ∠A + 60° = 180°
$$\frac{3}{2}$$ ∠A = 120°
∠A = 80°