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In a zoo, there are Rabbits and Pigeons. If heads are counted, there are 200 and if legs are counted, there are 580. How many pigeons are there?

A. 90

B. 100

C. 110

D. 120

Answer: Option C

Solution(By Examveda Team)

Heads Count = 200
Legs count = 580
Average Legs count for per head = $$\frac{{580}}{{200}}$$ = $$\frac{{29}}{{10}}$$
Alligation mcq solution image
Rabbits : Pigeons = $$\frac{{9}}{{10}}$$ : $$\frac{{11}}{{10}}$$ = 9 : 11
Number of Pigeons = $$200 \times \frac{{11}}{{20}}$$  = 110

This Question Belongs to Arithmetic Ability >> Alligation

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Comments ( 11 )

  1. Shalu Pahwa
    Shalu Pahwa :
    2 years ago

    https://byjus.com/question-answer/in-a-zoo-there-are-rabbits-and-pigeons-if-heads-are-counted-there-are-340/

  2. Abhijit Valvekar
    Abhijit Valvekar :
    3 years ago

    The simplest Way is -

    Total No of 4 Leg Animal(Rabbit ) = ((Total no of legs/2) -No. of heads)
    Rabbit = 580/2 - 200
    Rabbit = 90
    Pigeon = 200 - 90 = 110

  3. Beastboy Mayank
    Beastboy Mayank :
    3 years ago

    Let rabbit =x
    Pegion =200-x

    4x(because rabbit has 4 legs)+2(200-x)=580
    400+2x=580
    2x=180
    X=90

    Rabbit =90
    Pegion=110ans.

  4. Vishal Gupta
    Vishal Gupta :
    5 years ago

    Try to improve your solutions. Make it understandable.
    Comment section helped me in this question.

  5. Arijit Banerjee
    Arijit Banerjee :
    6 years ago

    Let pigeons= X
    Rabbits = y
    X+Y= 200 ......(1)
    2X+4Y =580 .... (2)
    Then
    4X + 4Y = 800
    2X + 4Y = 580
    - - -
    ------------------
    2X = 220
    X = 110

  6. Arijit Banerjee
    Arijit Banerjee :
    6 years ago

    Let pigeons= X
    Rabbits = y
    X+Y= 200 ......(1)
    2X+4Y =580 .... (2)
    Then
    4X + 4Y = 800
    2X + 2Y = 580
    - - -
    ------------------
    2X = 220
    X = 110

  7. MAnuj ShArma
    MAnuj ShArma :
    7 years ago

    Assuming that all are pigeons then total pigeons leg count will be 200*2(legs) = 400 legs.
    and all are Rabbits then total Rabbit's leg count will be 200*4(legs) = 800 legs.
    400 800
    /
    580(Given)
    /
    800-580 580-400
    =220 =180
    Ratio =11:9
    Ratio Sum 11+9=20
    which is given as 200
    So 11 parts will be 11×20020
    =110 Piegons.

  8. Aruna Gandem
    Aruna Gandem :
    7 years ago

    Nt understood

  9. Rohan Trehan
    Rohan Trehan :
    8 years ago

    Let no of rabbits be x
    pigeons be y
    x+y=200 ..... (1)
    Now, rabbits have 4 legs, whereas pigeons have 2 legs
    so, 4x+2y= 580 .... (2)
    W
    on solving eq 1 and 2
    we will get y=110

  10. Raman Kumar
    Raman Kumar :
    8 years ago

    (pigeons+rabbits)=200 (by heads)
    let the nos of pigeons =x
    then the nos of Rabbits = 200-x
    now total no of feets =2*nos of pigeons+4*nos of rabbits
    580 = x*2+4*(200-x)
    2x+800-4x=580
    -2x=-220
    x=220/2=110
    2x=220
    x=110

  11. Amna
    Amna :
    9 years ago

    not understand

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