In ΔABC, AD ⊥ BC, then
A. AB2 - BD2 = AC2 - CD2
B. AB2 + BD2 = AC2 - CD2
C. AB2 - BD2 = AC2 + CD2
D. AB2 - AC2 = BD2 + CD2
Answer: Option A
Solution(By Examveda Team)
In ΔADC AB2 = AD2 + BD2 - - - - - - - (1) In Right angled Δ ACD, AC2 = AD2 + BD2 - - - - - - - (2) By (1) - (2)AB2 - AC2 = BD2 - CD2 AB2 - BD2 = AC2 - CD2
This Question Belongs to Arithmetic Ability >> Triangles
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Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
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B. 70°
C. 60°
D. 80°
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In Right angled ÃŽ” ACD, Eqn. should be AC^2 = AD^2 + CD^2 instead of AC^2 = AD^2 + BD^2