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In ABC AD BC then

This question belongs to Arithmetic Ability Triangles
Triangles
?

In ΔABC, AD ⊥ BC, then

Answer & Solution
Correct Answer: Option A
In ΔADC
AB2 = AD2 + BD2 - - - - - - - (1)
In Right angled Δ ACD,
AC2 = AD2 + BD2 - - - - - - - (2)
By (1) - (2)
AB2 - AC2 = BD2 - CD2
AB2 - BD2 = AC2 - CD2
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1 Comment
Devendra Marghade
Devendra Marghade 10 years ago
In Right angled ÃŽ” ACD, Eqn. should be AC^2 = AD^2 + CD^2 instead of AC^2 = AD^2 + BD^2
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