In ABC AD BC then

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In ΔABC, AD ⊥ BC, then

A. AB² - BD² = AC² - CD²

B. AB² + BD² = AC² - CD²

C. AB² - BD² = AC² + CD²

D. AB² - AC² = BD² + CD²

Answer: Option A

Solution (By Examveda Team)

In ΔADC
AB² = AD² + BD² - - - - - - - (1)
In Right angled Δ ACD,
AC² = AD² + BD² - - - - - - - (2)
By (1) - (2)
AB² - AC² = BD² - CD²
AB² - BD² = AC² - CD²

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Comments (1)

Devendra Marghade:

10 years ago

In Right angled Î� ACD, Eqn. should be AC^2 = AD^2 + CD^2 instead of AC^2 = AD^2 + BD^2

In ABC AD BC then

In ΔABC, AD ⊥ BC, then

Solution (By Examveda Team)

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