In an isosceles triangle ΔABC, AB = AC and ∠A = 80°. The bisector of ∠B and ∠C meet at D. The ∠BDC is equal to.

A. 90°

B. 100°

C. 130°

D. 80°

Answer: Option C

Solution(By Examveda Team)

∵ AB = AC
   Point D is the incenter
∴ ∠BDC = 90° + $$\frac{1}{2}$$ ∠A
              = 90° + $$\frac{1}{2}$$ × 80°
              = 90° + 40°
              = 130°