In the adjoining figure AB, EF and CD are parallel lines. Given that GE = 5 cm, GC = 10 cm and DC = 18 cm, then EF is equal to:
A. 11 cm
B. 5 cm
C. 6 cm
D. 9 cm
Answer: Option D
Solution(By Examveda Team)
In ΔGEF and ΔGCD, we have∠EFG = ∠GCD (Alternative angle)
∠EFG = ∠CGD (Vertically opposite angles)
ΔGEF ~ ΔGCD
Thus,
$$\eqalign{ & \frac{{{\text{GE}}}}{{{\text{CG}}}} = \frac{{{\text{EF}}}}{{{\text{CD}}}} \cr & {\text{or, }}\frac{5}{{10}} = \frac{{{\text{EF}}}}{{18}} \cr & {\text{or,}}\,{\text{EF}} = 9\,{\text{cm}} \cr} $$
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Comments ( 5 )
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
triangle ABC and EFC are similar triangles.
Hence CE/EF=AC/AB( BE=15, EF=9, AB=15)
15/9=AC/15 ,
AC=25
triangle ABC and EFC are similar triangles.
Hence CE/EF=AC/AB( BE=15, EF=9, AB=15)
15/9=AC/15 ,
AC=25
Can you give answer for AC
wrong explanation
Can you give your own explanation? @Ravindra.