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In the adjoining figure AB, EF and CD are parallel lines. Given that GE = 5 cm, GC = 10 cm and DC = 18 cm, then EF is equal to:
mcq questions triangle Aptitude12

A. 11 cm

B. 5 cm

C. 6 cm

D. 9 cm

Answer: Option D

Solution(By Examveda Team)

In ΔGEF and ΔGCD, we have
∠EFG = ∠GCD (Alternative angle)
∠EFG = ∠CGD (Vertically opposite angles)
ΔGEF ~ ΔGCD
Thus,
$$\eqalign{ & \frac{{{\text{GE}}}}{{{\text{CG}}}} = \frac{{{\text{EF}}}}{{{\text{CD}}}} \cr & {\text{or, }}\frac{5}{{10}} = \frac{{{\text{EF}}}}{{18}} \cr & {\text{or,}}\,{\text{EF}} = 9\,{\text{cm}} \cr} $$

This Question Belongs to Arithmetic Ability >> Triangles

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Comments ( 5 )

  1. Mahesh Babu
    Mahesh Babu :
    7 years ago

    triangle ABC and EFC are similar triangles.
    Hence CE/EF=AC/AB( BE=15, EF=9, AB=15)
    15/9=AC/15 ,

    AC=25


  2. Mahesh Babu
    Mahesh Babu :
    7 years ago

    triangle ABC and EFC are similar triangles.
    Hence CE/EF=AC/AB( BE=15, EF=9, AB=15)
    15/9=AC/15 ,

    AC=25


  3. Ram Sai
    Ram Sai :
    8 years ago

    Can you give answer for AC

  4. Ravindra
    Ravindra :
    9 years ago

    wrong explanation

  5. Kumar Chandan
    Kumar Chandan :
    9 years ago

    Can you give your own explanation? @Ravindra.

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