In triangle ABC a straight line parallel to BC intersects AB and AC at D and E respectively. If AB = 2AD, then DE : BC is
A. 2 : 3
B. 2 : 1
C. 1 : 2
D. 1 : 3
Answer: Option C
Solution(By Examveda Team)
According to question,Given :
AB = 2AD
$$\frac{{AB}}{{AD}} = \frac{2}{1}$$
By applying B. P. T
$$\eqalign{ & \frac{{AD}}{{AB}} = \frac{{DE}}{{BC}} = \frac{{AE}}{{AC}} \cr & \frac{{DE}}{{BC}} = \frac{1}{2} \cr & \therefore DE:BC = 1:2 \cr} $$
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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