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In triangle ABC a straight line parallel to BC intersects AB and AC at D and E respectively. If AB = 2AD, then DE : BC is
Answer & Solution
Correct Answer:
Option
C
According to question,
Given :
AB = 2AD
$$\frac{{AB}}{{AD}} = \frac{2}{1}$$
By applying B. P. T
$$\eqalign{ & \frac{{AD}}{{AB}} = \frac{{DE}}{{BC}} = \frac{{AE}}{{AC}} \cr & \frac{{DE}}{{BC}} = \frac{1}{2} \cr & \therefore DE:BC = 1:2 \cr} $$
Given :
AB = 2AD
$$\frac{{AB}}{{AD}} = \frac{2}{1}$$
By applying B. P. T
$$\eqalign{ & \frac{{AD}}{{AB}} = \frac{{DE}}{{BC}} = \frac{{AE}}{{AC}} \cr & \frac{{DE}}{{BC}} = \frac{1}{2} \cr & \therefore DE:BC = 1:2 \cr} $$
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