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In ΔABC, AD is the internal bisector of ∠A, meeting the side BC at D. If BD = 5 cm, BC = 7.5 cm, then AB : AC is
Answer & Solution
Correct Answer:
Option
A
According to question,
By internal bisector property
$$\eqalign{ & \frac{{AB}}{{AC}} = \frac{{BD}}{{DC}} \cr & \frac{{AB}}{{AC}} = \frac{5}{{2.5}} \cr & \frac{{AB}}{{AC}} = \frac{2}{1} \cr & \therefore AB:AC = 2:1 \cr} $$
By internal bisector property
$$\eqalign{ & \frac{{AB}}{{AC}} = \frac{{BD}}{{DC}} \cr & \frac{{AB}}{{AC}} = \frac{5}{{2.5}} \cr & \frac{{AB}}{{AC}} = \frac{2}{1} \cr & \therefore AB:AC = 2:1 \cr} $$
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