In ΔABC and ΔPQR, ∠B = ∠Q, ∠C = ∠R. M is the midpoint on QR, If AB : PQ = 7 : 4, then $$\frac{{{\text{area}}\,\left( {\vartriangle ABC} \right)}}{{{\text{area}}\,\left( {\vartriangle PMR} \right)}}$$ is :
A. $$\frac{{35}}{8}$$
B. $$\frac{{35}}{{16}}$$
C. $$\frac{{49}}{{16}}$$
D. $$\frac{{49}}{8}$$
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & \frac{{{\text{area}}{\mkern 1mu} \left( {\vartriangle ABC} \right)}}{{{\text{area}}{\mkern 1mu} \left( {\vartriangle PMR} \right)}} \cr & = \frac{{{{\left( 7 \right)}^2}}}{{\frac{1}{2} \times {{\left( 4 \right)}^2}}} \cr & = \frac{{49}}{8} \cr} $$Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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