In triangle ABC, ∠BAC = 75°, ∠ABC = 45°, $$\overline {BC} $$ is produced to D. If ∠ACD = x°, then $$\frac{x}{3}$$% of 60° is

Solution (By Examveda Team)

According to question,

Given : ∠A = 75°,       ∠B = 45°
∴ ∠ACD = ∠A + ∠B
x° = ∠ACD = 120°
Now, $$\frac{x}{3}$$% of 60° is
= $$\frac{{120}}{3}$$ % of 60°
= 40% of 60°
= $$\frac{{40}}{{100}}$$ × 60°
= 24°