In ΔABC, ∠BAC = 90° and AB = $$\frac{1}{2}$$ BC, Then the measure of ∠ACB is :
A. 60°
B. 30°
C. 45°
D. 15°
Answer: Option B
Solution(By Examveda Team)
According to question,Given :
BAC is right angle triangle
AB = $$\frac{1}{2}$$BC
$$\eqalign{ & \frac{{AB}}{{BC}} = \frac{1}{2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{P}{H} = \frac{1}{2} \cr & \sin \theta = \frac{P}{H} = \frac{1}{2} \cr & \sin \,{30^ \circ } = \frac{1}{2} \cr & \therefore \theta = \angle ACB = {30^ \circ } \cr} $$
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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