In ΔABC, the line parallel to BC intersect AB & AC at P & Q respectively. If AB : AP = 5 : 3, then AQ : QC is:
A. 3 : 2
B. 1 : 2
C. 3 : 5
D. 2 : 3
Answer: Option A
Solution (By Examveda Team)
$$\eqalign{ & \frac{{AP}}{{PB}} = \frac{{AQ}}{{QC}} \cr & \frac{{AQ}}{{QC}} = \frac{3}{2} \cr & AQ:QC = 3:2 \cr} $$
This Question Belongs to Arithmetic Ability >> Triangles
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