In triangle PQR, points A, B and C are taken on PQ, PR and QR respectively such that QC = AC and CR = CB. If ∠QPR = 40°, then ∠ACB is equal to:
A. 140°
B. 40°
C. 70°
D. 100°
Answer: Option D
Solution(By Examveda Team)
According to question,In ΔPQR
x + y + 40° = 180°
x + y = 140° . . . . . . . (i)
In ΔAQC
x + x + ∠C = 180°
∠C = 180° - 2x . . . . . . . . (ii)
In ΔBCR
y + y + ∠C = 180°
∠C = 180° - 2y . . . . . . . . (iii)
But ∠ACB = 180° - 180° + 2x - 180° +2y
∠ACB = 2x + 2y - 180°
∠ACB = 2(x + y) - 180° . . . . . . . . . (iv)
Put the value of equation (i) in equation (iv)
∠ACB = 2 × 140° - 180°
∠ACB = 280° - 180°
∠ACB = 100°
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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