Incenter of ΔABC is I. ∠ABC = 90° and ∠ACB = 70°. ∠BIC is:
A. 115°
B. 100°
C. 110°
D. 105°
Answer: Option B
Solution (By Examveda Team)
∵ Sum of all angles of a triangle = 180°So, ∠BAC = 180 - (90 + 70)
∠BAC = 20°
So, ∠BIC = 90 + $$\frac{1}{2}$$ ∠A
∠BIC = 90° + $$\frac{1}{2}$$ × 20°
∠BIC = 100°
This Question Belongs to Arithmetic Ability >> Triangles
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