Let O be the in-centre of a triangle ABC and D be a point on the side BC of ΔABC, such that OD ⊥ BC. If ∠BOD = 15°, then ∠ABC = ?
A. 75°
B. 45°
C. 150°
D. 90°
Answer: Option C
Solution (By Examveda Team)
According to question,
Given : ∠BOD = 15°
∴ ∠BDO + ∠DOB + ∠DBO = 180°
∠DBO = 75°
∠ABC = 2 × ∠DBO
∠ABC = 2 × 75°
∠ABC = 150°
This Question Belongs to Arithmetic Ability >> Triangles
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