O is the incentre of ΔABC and ∠A = 30°, then ∠BOC is
A. 100°
B. 105°
C. 110°
D. 90°
Answer: Option B
Solution (By Examveda Team)
According to question,Given:
∴ ∠BOC = 90° + $$\frac{1}{2}$$ ∠A
∠BOC = 90° + $$\frac{1}{2}$$ × 30°
∠BOC = 90° + 15°
∠BOC = 105°
This Question Belongs to Arithmetic Ability >> Triangles
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