The isentropic enthalpy drop in moving blade is two-third of the isentropic enthalpy drop in fixed blades of a turbine. The degree of reaction will be
A. 0.4
B. 0.56
C. 0.67
D. 1.67
Answer: Option A
This Question Belongs to Mechanical Engineering >> Steam Boilers, Engines, Nozzles And Turbines
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Rd = Hm/(Hf+Hm).
So,
Rd = (2/3)Hf/{(2/3)Hf+Hf}.
= 0.4.
Because, Given that.
Hm = 2/3 Hf.