The number of three way crosses are

A. $$\frac{{{\text{n}}\left( {{\text{n}} - 1} \right)\left( {{\text{n}} - 2} \right)}}{2}$$

B. $$\frac{{{\text{n}}\left( {{\text{n}} + 1} \right)\left( {{\text{n}} + 2} \right)}}{2}$$

C. $$\frac{{{\text{n}}\left( {{\text{n}} - 1} \right)\left( {{\text{n}} - 2} \right)\left( {{\text{n}} - 3} \right)}}{8}$$

D. $$\frac{{{\text{n}}\left( {{\text{n}} - 1} \right)\left( {{\text{n}} + 2} \right)\left( {{\text{n}} - 3} \right)}}{6}$$

Answer: Option A