The ratio of driving tensions for flat belts, neglecting centrifugal tension, is (where T₁ and T₂ = Tensions on the tight and slack sides of belt respectively, $$\mu $$ = Coefficient of friction, between the belt and pulley and $$\theta $$ = Angle of contact)

A. $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \mu \theta $$

B. $$\log \frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \mu \theta $$

C. $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = {\text{e}}\mu \theta $$

D. $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \log \mu \theta $$

Answer: Option C