The ratio of milk and water in mixture of four containers are 5 : 3, 2 : 1, 3 : 2 and 7 : 4 respectively. In which container is the quantity of milk, relative to water, minimum ?
A. First
B. Second
C. Third
D. Forth
Answer: Option C
Solution(By Examveda Team)
∴According to the question,Container :
$$\eqalign{ & \,\,\,\,\,\,\,\,{\text{I}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{II}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{III}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{IV}} \cr & {\text{M}}\,:\,{\text{W}}\,\,\,{\text{M}}\,:\,{\text{W}}\,\,\,{\text{M}}\,:\,{\text{W}}\,\,\,{\text{M}}\,:\,{\text{W}} \cr & \,\,\,\,5:3\,\,\,\,\,\,\,\,\,\,\,2:1\,\,\,\,\,\,\,\,\,\,\,3:2\,\,\,\,\,\,\,\,\,\,7:4 \cr} $$
$$\eqalign{ & {\bf{Container}}\,\,({\text{I}}): \cr & \frac{{{\text{Milk}}}}{{{\text{Water}}}} = \frac{5}{3} = 1.67 \cr & \cr & {\bf{Container}}\,\,({\text{II}}): \cr & \frac{{{\text{Milk}}}}{{{\text{Water}}}} = \frac{2}{1} = 2 \cr & \cr & {\bf{Container}}\,\,({\text{III}}): \cr & \frac{{{\text{Milk}}}}{{{\text{Water}}}} = \frac{3}{2} = 1.5 \cr & \cr & {\bf{Container}}\,\,({\text{IV}}): \cr & \frac{{{\text{Milk}}}}{{{\text{Water}}}} = \frac{7}{4} = 1.75 \cr} $$
∴ The quantity of milk relative to water minimum in container third
Related Questions on Alligation
A. $$\frac{{1}}{{2}}$$ kg
B. $$\frac{{1}}{{8}}$$ kg
C. $$\frac{{3}}{{14}}$$ kg
D. $$\frac{{7}}{{9}}$$ kg
A. 81 litres
B. 71 litres
C. 56 litres
D. 50 litres
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