ΔABC is similar to ΔDEF. If the sides of ΔABC, that is AB, BC and CA, are 3, 4 and 5 cms respectively, what would be the perimeter of the ΔDEF, if the side DE measures 12 cms ?
A. 24 cms
B. 30 cms
C. 36 cms
D. 48 cms
Answer: Option D
Solution(By Examveda Team)
Perimeter of ΔABC
= 3 + 4 + 5
= 12
$$\eqalign{ & \frac{{{\text{Perimeter}}\,{\text{of}}\,\vartriangle ABC}}{{{\text{Perimeter}}\,{\text{of}}\,\vartriangle DEF}} = \frac{{AB}}{{DE}} \cr & \frac{{12}}{{{\text{Perimeter}}\,{\text{of}}\,\vartriangle DEF}} = \frac{3}{{12}} \cr} $$
Perimeter of ΔDEF = 48 cms
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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