ΔABC is similar to ΔDEF is area of ΔABC is 9 sq. cm. and area of ΔDEF is 16 sq. cm. and BC = 21 cm. Then the length of EF will be:
A. 5.6 cm
B. 2.8 cm
C. 3.7 cm
D. 1.4 cm
Answer: Option B
Solution (By Examveda Team)
∵ ΔABC ≅ ΔDEF
$$\eqalign{ & \therefore \frac{{AB}}{{DE}} = \frac{{BC}}{{EF}} = \frac{{\sqrt 9 }}{{\sqrt {16} }} \cr & = \frac{{2.1}}{{EF}} = \frac{3}{4} \cr & EF = 2.8\,{\text{cm}} \cr} $$
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?

A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd


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