Direction (1 - 5): Study the following bar graph and the table carefully and answer the questions given below:
Time Taken (in hours) by 6 Vehicles on Two Different Days
Distance Covered (in km) by 6 Vehicles on Each Day
Vehicles | Day 1 | Day 2 |
A | 832 | 864 |
B | 516 | 774 |
C | 693 | 810 |
D | 552 | 765 |
E | 935 | 546 |
F | 703 | 636 |
What was the speed of vehicles C on Day 2 in terms of metres per second ?
A. 15.3 m/s
B. 12.8 m/s
C. 11.5 m/s
D. 13.8 m/s
E. None of these
Answer: Option E
Solution(By Examveda Team)
$$\eqalign{ & \text{Speeds of vehicles on Day 1:} \cr & \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr & \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr & \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr & \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr & \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr & \cr & \text{Speed of vehicles on Day 2:} \cr & \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr & \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr & \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr & \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr & \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$$$\eqalign{ & \text{Speed of C on Day 2} \cr & = 45 \text{ km/hr} \cr & = \left(45\times\frac{5}{18}\right) \text{m/sec} \cr & = \frac{25}{2} \text{ m/s} \cr & = 12.5 \text{ m/s} \cr} $$
Related Questions on Bar Chart
The percent increase in population from 1991 to 2001 is:
A. 24.8 crores
B. 20 crores
C. 13.6 crores
D. 22.9 crores
A. 1971
B. 1981
C. 1991
D. 2001
A. 1971
B. 1981
C. 1991
D. 1961
Per year increase in population from the year 1951 to 2001 is
A. 8100000
B. 7600000
C. 8900000
D. 6700000
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