What will be the output of the following Java code?
class exception_handling
{
public static void main(String args[])
{
try
{
int a = args.length;
int b = 10 / a;
System.out.print(a);
try
{
if (a == 1)
a = a / a - a;
if (a == 2)
{
int c = {1};
c[8] = 9;
}
}
catch (ArrayIndexOutOfBoundException e)
{
System.out.println("TypeA");
}
catch (ArithmeticException e)
{
System.out.println("TypeB");
}
}
}
}
Note : Execution command line : $ java exception_handling one
class exception_handling
{
public static void main(String args[])
{
try
{
int a = args.length;
int b = 10 / a;
System.out.print(a);
try
{
if (a == 1)
a = a / a - a;
if (a == 2)
{
int c = {1};
c[8] = 9;
}
}
catch (ArrayIndexOutOfBoundException e)
{
System.out.println("TypeA");
}
catch (ArithmeticException e)
{
System.out.println("TypeB");
}
}
}
}A. TypeA
B. TypeB
C. Compilation Error
D. Runtime Error
Answer: Option C
This Question Belongs to Java Program >> Exceptions
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Comments ( 1 )
A. An error that occurs during runtime
B. An error that occurs during compilation
C. A warning issued by the compiler
D. A type of loop
What is the purpose of the "try" block in exception handling?
A. It catches exceptions and handles them
B. It specifies the exception type
C. It contains the code that might throw an exception
D. It specifies the exception message
In Java, can a method declare multiple exceptions using the "throws" keyword?
A. Only if the method is marked as "static"
B. Yes, a method can declare multiple exceptions separated by commas
C. Only if the exceptions are marked as "final"
D. Only if the method is marked as "static"
Plz explain compliation error Due to .?