What will be the output of the following PHP code ?
<?php
$x = 5;
function fun()
{
echo "$x";
}
fun();
?>
<?php
$x = 5;
function fun()
{
echo "$x";
}
fun();
?>
A. 0
B. 5
C. Nothing
D. Error
Answer: Option C
Solution(By Examveda Team)
The variable x is not defined inside the function fun(), therefore nothing is printed on the screen.This Question Belongs to PHP >> Operators And Expressions In Php
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