When a beam of rectangular cross-section of width b and depth d, is subjected to a shear force F, the maximum shear stress induced will be
A. $$\frac{{\text{F}}}{{{\text{bh}}}}$$
B. $$\frac{{{\text{3F}}}}{{{\text{2bh}}}}$$
C. $$\frac{{{\text{2F}}}}{{{\text{bh}}}}$$
D. $$\frac{{{\text{4F}}}}{{{\text{bh}}}}$$
Answer: Option B

tmax = 3/2 t average for rectangular beam.
t average = Force / Area of rectangle
= F / b h