Which of the following expressions for total binding energy B of a nucleus is correct (a1, a2, a3, a4 > 0?
A. $$B = {a_1}A - {a_2}{A^{2/3}} - {a_3}\frac{{Z\left( {Z - 1} \right)}}{{{A^{1/3}}}} - {a_4}\frac{{{{\left( {A - 2Z} \right)}^2}}}{A} + \delta $$
B. $$B = {a_1}A + {a_2}{A^{2/3}} - {a_3}\frac{{Z\left( {Z - 1} \right)}}{{{A^{1/3}}}} - {a_4}\frac{{{{\left( {A - 2Z} \right)}^2}}}{A} + \delta $$
C. $$B = {a_1}A + {a_2}{A^{1/3}} - {a_3}\frac{{Z\left( {Z - 1} \right)}}{{{A^{1/3}}}} - {a_4}\frac{{{{\left( {A - 2Z} \right)}^2}}}{A} + \delta $$
D. $$B = {a_1}A - {a_2}{A^{1/3}} - {a_3}\frac{{Z\left( {Z - 1} \right)}}{{{A^{1/3}}}} - {a_4}\frac{{{{\left( {A - 2Z} \right)}^2}}}{A} + \delta $$
Answer: Option A

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